wait for the cycle to fully complete
Posts by Jason Mileshko
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I've had the same issue
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Did you figure this out?
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Mathematically, the situation is that if m and v are the mean and variance, respectively, of a lognormally distributed variable Y, can you compute the usual parameters for log(Y)? The answer is yes. In terms of μ and σ, the mean of Y is m = exp(μ + σ2/2) and the variance is v = (exp(σ2) -1) exp(2μ + σ2). You can invert these formulas to get μ and σ as functions of m and v.