Parity input

  • No ......

    You need to look at the program number in the binary form

    0000 zero

    0001 one

    0010 two

    0011 three

    0100 four

    0101 five

    0110 six

    0111 seven

    1000 eight


    Then you need to count number of bits that are set in each case. Parity is set in accordance to that.

    For example value seven has 3 bits set

    Three is an odd number so value of parity would need to be set according to that and chosen parity method (even/odd).

    If using even parity, parity bit would need need to be set to 1 so that total number of all bits is even (including bits in PGNO and the parity bit itself).

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