Need help with PR[i,j]

  • I know that the i represents the position register number.


    The j represents the position register element number. In my situation, j represents the Z position.


    Overview of lab:

    Create PR [4: OFFSET]: Created the offset point

    Then used PR[i,j]

    I used PR [4: offset] as i, and 3 as the j.

    The code would be like this: PR[4, 3: OFFSET] + 15: Does that mean I offset 15 mm in z position referenced from point 4(offset I created in PR[4])?


    Can someone explain in like 5 year old term how PR[i,j] work?


    Also, what is the difference from the code listed from above and this one? PR[4, 3: OFFSET] = 0 or 15?

  • AD
  • This line below is incomplete and would be a syntax error.

    : PR[4, 3: OFFSET] + 15



    This line is complete. It's adds 15 to the current z value.

    :PR[4, 3: OFFSET] = PR[4, 3: OFFSET] + 15;


    This line is also complete. It sets the z value to 15.

    :PR[4, 3: OFFSET] = 15;

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